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Question

Prove that : (sin4θ+cos4θ)12sin2θcos2θ=1

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Solution

L.H.S
sin4θ+cos4θ12sin2θcos2θ=(sin2θ+cos2θ)22sin2θcos2θ12sin2θcos2θ=12sin2θcos2θ12sin2θcos2θ=1

Hence, proved.

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