Prove that - sin x-ysin x-y-tan x -tan ytan x -tan y

LHS : sin (x+y)sin (x y) =sin x cos y +cos x sin ysin x cos y cos x sin y =sin x cos y +cos x sin ycos x cos ysin x cos y cos x sin ycos x cos y ...

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Tangent, Cotangent, Secant, Cosecant in Terms of Sine and Cosine

Prove that : ...

Question

Prove that :
$\frac{sin (x + y)}{sin (x - y)} = \frac{tan x + tan y}{tan x - tan y}$

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\frac{s i n (x + y)}{s i n (x - y)} = \frac{a + b}{a - b},

\frac{t a n x}{t a n y} = \frac{a}{b} .

\frac{sin (x + y)}{sin (x - y)} = \frac{tan x + tan y}{tan x - tan y}

\frac{sin (x + y)}{sin (x - y)} = \frac{tan x + tan y}{tan x - tan y}

\frac{s i n (x + y)}{s i n (x - y)} = \frac{a + b}{a - b}, then \frac{t a n x}{t a n y} =

cos x = tan y, cot y = tan z

cot z = tan x

sin x =

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