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Question

Prove that equal chords of a circle subtend equal angles at the centre


Solution

In $$\Delta AOB $$ and $$\Delta COD$$,
AB$$=$$CD (Given)
AO$$=$$CO (radius)
OB$$=$$OD (radius)
By S.S.S congruency, $$\Delta  AOB \cong \Delta COD$$
$$ \Rightarrow \angle AOB=\angle COD$$.

1207956_1349821_ans_6e05989d05754922a9fcb48ab72c934d.jpg

Mathematics

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