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Question

Prove that following identities:

sin 5A=5 cos4 A sin A10 cos2 A sin3 A+sin5A

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Solution

We have to prove that

sin 5A=5 cos4 A sin A10 cos2 A sin3 A+sin5A

L.H.S. = sin 5A = sin (3A + 2A)

= sin 3A cos 2A+cos 3A. sin 2A

=(3 sin A4 sin3A)(2 cos2A1)+(4 cos3A3 cos A)2 sin A cos A.=3 sin A+4 sin3 A+6 sin A cos2 A8 sin3 A cos2 A+8 cos4 A sin A6 cos2 A sin A=8 cos4 A sin A8 sin3 A cos2 A3 son A+4 sin3 A=5 cos4A sinA10 sin3 A cos2 A3 sin A+3 cos4 A+4 sin3A+2 sin3 A cos2 A=5 cos4A sin A10 sin3 A cos2 A3 sin A(1cos2A)+2 sin3A(2+cos2A)=5 cos4 A sin A10 sin3 A cos2 A3 sin3 A(1+cos2A)+2 sin3A(2+cos2A)

=5 cos4 A sin A10 sin3 A cos2 Asin3 A[3(1+cos2A)2(2+cos2A)]=5 cos4 A sin A10 sin3 A cos2 Asin3 A[3+3cos2A42 cos2A]=5 cos4 A sin A10 sin3 A cos2 Asin3 A[cos2A1]=5 cos4 A sin A10 sin3 A cos2 A+sin5 A=RHS


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