Prove that-sin 2 -1-cos 2 -tan-

LHS, sin 2 θ/1 + cos 2θ = 2 sin θ cos θ/2 cos^2 θ =sin θ/cos θ = tan θ = RHS ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Tangent, Cotangent, Secant, Cosecant in Terms of Sine and Cosine

Prove that:si...

Question

Prove that:

$\frac{s i n 2 θ}{1 + c o s 2 θ} = t a n θ$

Open in App

Solution

Suggest Corrections

Similar questions

\sqrt{\frac{1 - cos 2 θ}{1 + cos 2 θ}} = tan θ

\frac{c o s^{2} θ}{1 - t a n θ} + \frac{s i n^{3} θ}{s i n θ - c o s θ} = 1 + s i n θ c o s θ

\frac{1 - c o s 2 θ + s i n 2 θ}{1 + c o s 2 θ + s i n 2 θ} = t a n θ

x = \sqrt{{cos}^{2} θ + \sqrt{{cos}^{2} θ {\sqrt{cos}}^{2} θ + . . . \infty}}

y = \sqrt{sec θ - \sqrt{sec θ - \sqrt{sec θ - . . . \infty}}}

(x^{2} - x) (y^{2} + y) = 1

z = \sqrt{tan θ + \sqrt{tan θ + \sqrt{tan θ + . . . \infty}}}

z^{2} = tan θ + z

Join BYJU'S Learning Program