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Question

Prove that : sin A2sin3A2cos3Acos A=tan A.


Solution

L.H.S = sin A2sin3A2cos3Acos A
           = sin A(12 sin2A)cos A(2cos2A1)
=sin Acos A(12sin2A)[2(1sin2A)1]         [cos2A=1sin2A]
=sin Acos A(12sin2A)(22sin2A1)
=sin Acos A(12sin2A)(12sin2A)
=tan A= R.H.S   Hence Proved.
 

Mathematics

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