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Question

Prove that :
a0x2(ax)ndx=2an+3(n+1)(n+2)(n+3)

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Solution

a0x2(ax)ndx=⎢ ⎢x2(ax)n+1n+1+(2x(ax)n+2)n+2+2x(ax)n+3n+3⎥ ⎥a0
=⎢ ⎢x2(ax)n+1n+1+(2x(ax)n+2)n+2(n+1)2a(ax)n+3(n+1)(n+2)n+3⎥ ⎥a0
=⎢ ⎢0(2a(n+3))(n+1)(n+2)n+3⎥ ⎥
=2a(n+3)(n+1)(n+2)n+3
Hence, solved.


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