Prove that. tan70^°= tan20^° +2 tan 50^°

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tan 70^{\circ} = tan 20^{\circ} + 2 tan 50^{\circ}

tan 20^{\circ} tan 35^{\circ} tan 45^{\circ} tan 55^{\circ} tan 70^{\circ} = 1

Prove that $t a n 70^{\circ} = t a n 20^{\circ} + 2 t a n 50^{\circ} .$
Or

Prove that $1 + c o s 2 x + c o s 4 x + c o s 6 x = 4 c o s x c o s 2 x c o s 3 x$

tan 70^{\circ} = tan 20^{\circ} + 2 tan A^{\circ}

A

sin (50^{\circ} + θ) - cos (40^{\circ} - θ) + tan 1^{\circ} tan 10^{\circ} tan 20^{\circ} tan 70^{\circ} tan 80^{\circ} tan 89^{\circ} = 1

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