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Question

Prove that the following vectors are coplanar:
(i) 2i^-j^+k^, i^-3j^-5k^ and 3i^-4j^-4k^

(ii) i^+j^+k^, 2i^+3j^-k^ and -i^-2j^+2k^

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Solution

(i) Given the vectors P2i^ - j^ + k^, Qi^ - 3j^ - 5k^ and R3i^ - 4j^ - 4k^.
We know the three vectors are coplanar if one of them is expressible as a linear combination of the other two. Let,
2i^ - j^ + k^ = x i^ - 3j^ - 5k^ + y 3i^ - 4j^ - 4k^. = i^ x + 3y + j^ -3x-4y + k^ -5x-4y.
x+ 3y = 2, -3x-4y =-1, -5x-4y=1 [Equating the coefficients of i^, j^, k^ respectively]
Solving first two of these equation, we get x=-1 , y=1. Clearly these two values satisfy the third equation.
Hence, the given vectors are coplanar.

(ii) Given the vectors Pi^ + j^ + k^, Q2i^ + 3j^ - k^ and R-i^ - 2j^ + 2k^.
We know the three vectors are coplanar if one of them is expressible as a linear combination of the other two. Let,
i^ + j^ + k^ = x 2i^ + 3j^ - k^ + y -i^ - 2j^ + 2k^. = i^ 2x - y + j^ 3x - 2y + k^ -x + 2y.
2x- y =1 , 3x- 2y = 1, -x + 2y = 1 [ Equating the coefficients of i^, j^ , k^ respectvely]
Solving first two of these equation , we get x=1, y=1. Clearly these two values satisfy the third equation.
Hence, the given vectors are coplanar.

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