Question

Prove that $x^{\log y-\log z}.x^{\log z-\log x}.x^{\log x-\log y}=1$.

Answer 1

Now,

$x^{\log y-\log z}.x^{\log z-\log x}.x^{\log x-\log y}$

$=x^{(\log y-\log z)+(\log z-\log x)+(\log x-\log y)}$ [ Using product rule of exponent]

$=x^0$

$=1$.