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Question

Prove the construction method used for constructing similar triangles of the given ratio of corresponding sides.


Solution

img

BCCC=31 

Therefore, BCBC=BC+CCBC=1+CCBC=1+13=43,          i.e., BCBC=34  

Also C'A' is parallel to CA. Therefore, A'BC' ~  ABC.

So, ABAB=ACAC=BCBC=34 

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