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Question

Prove the followings,
i) (a+b)2+(ab)2=2(a2+b2)
ii) (a+b)2(ab)2=4ab

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Solution

We have,

i) (a+b)2+(ab)2
=(a2+2ab+b2)+(a22ab+b2)
=2(a2+b2)

ii) (a+b)2(ab)2
=(a2+2ab+b2)(a22ab+b2)
=a2+2ab+b2a2+2abb2
=4ab.

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