{ Q }19/28 If relative decrease in vapour pressure is }0.4}{ for a solution containing }1 mol }NaCl in }3 mol of }H_2O}{ then % ionization of }NaCl is

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Q. If relative decrease in vapour pressure is

0.4

for a solution containing

1

mol

N a C l

3

mol

H_{2} O

N a C l

is_____ % ionized.

Q. If relative decrease in vapour pressure is 0.8 for a solution containing equimolar

N a C l a n d H_{2} O

, then percentage ionization of

N a C l

is:

Q. If relative decrease in V.P is 0.4 for a solution containing 1 mol

N a C l

in 3 mol of H

_{2}

O. Calculate % ionization of

N a C l

Relative decrease in vapor pressure is 0.4 for a solution containing 1 mole AB in 3 mol $H_{2} O$ , therefore AB is ionised at the extent(percentage) of:

Q. Addition of a non-volatile solute to a solvent always increases the colligative property such as

π, \frac{Δ P}{P^{\circ}}, Δ T_{b}

and

Δ T_{f}

. All these colligative properties are directly proportional to the molality. The increase in colligative properties is due to increase in number of solute particles.
If relative decrease in vapour pressure is 0.4 for a solution containing 1 mole NaCl in 3 moles of

H_{2} O

, then what is the percentage ionization of NaCl?

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