1st Equation of Motion

Q.33. A proje...

Question

Q.33. A projectile is projected with certain velocity at an angle $θ$ with the horizontal from the ground. If its time of flight is T then the magnitude of change in its velocity when body reaches to ground again is (g is acceleration due to gravity)
(1) gT
(2) $\frac{g T}{2}$
(3) 2gT
(4) $\frac{g^{2}}{T}$

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Solution

Dear Student,
$w h e n b o d y t o u c h e s t h e g r o u n d i t w i l l m a k e a n g l e θ w i t h h o r i z o n t a l s o a n g l e b e t w e e n i n i t i a l v e l o c i t y a n d f i n a l v e l o c i t y i s 2 θ h e n c e d i f f e r e n c e i n t h e i r v e l o c i t i e s ∆ v = \sqrt{u^{2} + u^{2} - 2 u^{2} \cos (2 θ)} = 2 u \sin (θ) b u t a c c o r d i n g t o q u e s t i o n t i m e o f f l i g h t = T = \frac{2 u \sin (θ)}{g} \Rightarrow 2 u \sin (θ) = g T h e n c e ∆ v = g T$

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