Question

Q. A bullet of 50 g is fired from a revolver with a velocity of 100 ms^-1 into an ice block at 0° C. The bullet stops after it gets embedded into. ice. Assuming that all the kinetic energy of the bullet is converted into heat energy which is absorbed by the meeting ice, find the quantity of the ice that just melts.
​( Taken latent heat of fusion of ice as 80 cal g^-1)

Answer 1

Dear Student,
$$\begin{gathered} \frac{1}{2}m{v}^2=m\text{'}L \\ \frac{{\displaystyle 1}}{{\displaystyle 2}}\times 50\times {\left(10000\right)}^2=m\text{'}\times 80 \\ m\text{'}=31250kg \end{gathered}$$
Regard