CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

Q. Prove that one of any three consecutive positive integers must be divisible by 3 .


Solution

Let three consecutive positive integers be n+ 1 and n + 2.

Whenever a number is divided by 3, the remainder obtained is either 0 or 1 or 2.

∴ n = 3p or 3p + 1 or 3p + 2, where p is some integer.

If n = 3p, then n is divisible by 3.

If n = 3p + 1, then + 2 = 3p + 1 + 2 = 3+ 3 = 3(p + 1) is divisible by 3.

If n = 3p + 2, then n + 1 = 3p + 2 + 1 = 3p + 3 = 3(p + 1) is divisible by 3.

So, we can say that one of the numbers among n+ 1 and n + 2 is always divisible by 3.


Mathematics

Suggest Corrections
thumbs-up
 
0


similar_icon
Similar questions
View More


similar_icon
People also searched for
View More



footer-image