Q2- If 20 g of calcium carbonate reacted with 20 g of HCl- how many grams of CO2 can be produced according to the reaction-CaCO3 -160- -160-2HCl -160- -8594- -160- -160-CaCl2 -160- -160-H2O -160- -160-CO2

Dear Student, Given, nbsp; nbsp; nbsp; CaCO3(s) nbsp;+ 2HCl(aq) nbsp; rarr; CaCl2(aq) nbsp;+ CO2(g) nbsp;+ H2O(l) Here, 1 mole of CaCO3 nbs ...

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Standard XII

Chemistry

Abnormal Colligative Properties

Q2. If 20 g o...

Question

Q2. If 20 g of calcium carbonate reacted with 20 g of HCl, how many grams of CO₂ can be produced according to the reaction,
$C a C O_{3} + 2 H C l \underset{}{\to} C a C l_{2} + H_{2} O + C O_{2}$

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Solution

Dear Student,

Given,
CaCO_3(s) + 2HCl_(aq) → CaCl₂_(aq)+ CO₂_(g) + H₂O_(l)

Here, 1 mole of CaCO₃ reacts with 2 moles of HCl

Number of moles of CaCO₃ = (20 g) / (100 g/mol)
= 0.2 moles
Ratio of CaCO₃ : HCl = 1 : 2
Moles of HCl required = 0.2 x 2 = 0.4

Actual Number of moles of HCl = (20 g) / (36.6 g/mol)
= 0.55 moles
Therefore,
HCl is in excess and hence, CaCO₃ is the limiting reagent
Moles of CO₂ = 0.2 moles
Hence,
Mass of CO₂ = 0.2 mol x 44 g/mol
= 8.8 g

Regards,

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Similar questions

Q. If 20 g of

C a C O_{3}

is treated with 20 g of HCl, how many grams of

C O_{2}

can be generated according to the following equation ?

C a C O_{3} + 2 H C l \to C a C l_{2} + H_{2} O + C O_{2}

(Molecular masses;

C a C O_{3} = 100 u, H C l = 36.5 u C O_{2} = 44 u)

Calcium carbonate reacts with aqueous HCl to give CaCl₂and CO₂according to the reaction, CaCO₃+ 2HCl --> CaCl₂+ H₂O

What mass of CaCO3 is required to react completely with 25mL of 0.75 HCl?

C a C O_{3} + 2 H C l \to C a C l_{2} + H_{2} O + C O_{2}

4.0

moles of HCl are available for the reaction with an unlimited supply of

C a C O_{3}

, how many moles of

C O_{2}

can be produced at STP?

Q. How many grams of

C O_{2}

can be prepared from

150

grams of calcium carbonate (

C a C O_{3}

) reacting with an excess of hydrochloric (

H C l

) acid solution?

Calcium carbonate reacts with aqueous $HCl$ to give ${CaCl}_{2}$ and ${CO}_{2}$ according to the reaction given below

$\underset{Calcium Carbonate}{{CaCO}_{3} (s)} + \underset{Hydrochloric acid}{2 HCl (aq)} ⟶ \underset{Calcium Chloride}{{CaCl}_{2} (aq)} + \underset{Carbon dioxide}{{CO}_{2} (g)} + \underset{Water}{H_{2} O (l)}$

What mass of ${CaCO}_{3}$ is required to react completely with 25 mL of 0.75 M HCl?

1) 0.6844

2) 0.9375

3) 0.4265

4) 0.2785

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Q2. If 20 g of calcium carbonate reacted with 20 g of HCl, how many grams of CO2 can be produced according to the reaction, CaCO3 + 2HCl → CaCl2 + H2O + CO2

Q2. If 20 g of calcium carbonate reacted with 20 g of HCl, how many grams of CO₂ can be produced according to the reaction,
$C a C O_{3} + 2 H C l \underset{}{\to} C a C l_{2} + H_{2} O + C O_{2}$