CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Division of a Monomial by Another Monomial

Question 16Th...

Question

Question 16
The factorization of $4 x^{2} + 8 x + 3$ is

A) $(x + 1) (x + 3)$
B) $(2 x + 1) (2 x + 3)$
C) $(2 x + 2) (2 x + 5)$
D) $(2 x - 1) (2 x - 3)$

Open in App

Solution

The answer is B.
$4 x^{2} + 8 x + 3 = 4 x^{2} + 6 x + 2 x + 3$ [by splitting middle term]
$= 2 x (2 x + 3) + 1 (2 x + 3)$
$= (2 x + 3) (2 x + 1)$

Suggest Corrections

thumbs-up

2

Similar questions

$(4 x^{2} + 4 x - 3)$ =?

(a) $(2 x - 1) (2 x - 3)$

(b) $(2 x + 1) (2 x - 3)$

(c) $(2 x + 3) (2 x - 1)$

(d) None of these

The factors of the polynomial 4x²+ 12x + 9 are

Find the factors of $6 x^{2} - 13 x + 6 = 0$

Factorise $2 x^{2} - 7 x + 6$

\frac{x + 2}{(x + 1) (2 x + 3)} - \frac{2 x + 3}{(x + 1) (x + 2)} + \frac{3 x + 5}{(2 x + 3) (x + 2)}

View More

Join BYJU'S Learning Program

explore_more_icon

Explore more

Division of a Monomial by Another Monomial

Standard VIII Mathematics

Join BYJU'S Learning Program

CrossIcon