CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Question 22 (i)
(i) Complete the following table:
Event: Sum of 2 dice23456789101112Probability136536136

Open in App
Solution

Total favourable outcomes of throwing two dice are:
(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)
(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)
(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)
(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)
(5,1) (5,2) (5,3) (5,4) (5,5 ) (5,6)
(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)
Total number of favourable outcomes = 36
(i) Favourable outcomes of getting the sum as 3 = 2
Hence, P (getting the sum as 3) = 236=118
Favourable outcomes of getting the sum as 4 = 3
Hence, P (getting the sum as 4) = 336=112
Favourable outcomes of getting the sum as 5 = 4
Hence, P (getting the sum as 5) = 436=19
Favourable outcomes of getting the sum as 6 = 5
Hence, P (getting the sum as 6)=536
Favourable outcomes of getting the sum as 7 = 6
Hence, P (getting the sum as 7) = 636=16
Favourable outcomes of getting the sum as 9 = 4
Hence, P (getting the sum as 9) = 436=19
Favourable outcomes of getting the sum as 10 = 3
Hence, P (getting the sum as 10) = 336=112
Favourable outcomes of getting the sum as 11 = 2
Hence, P (getting the sum as 11) = 236=118
Event: Sum of 2 dice23456789101112Probability136236336436536636536436336236136

flag
Suggest Corrections
thumbs-up
11
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon