Question 3.2

Identify the substance that is oxidized and the substance that is reduced in the following reaction:

$CuO(s) + H_{2} (g) \to Cu(s) + H_{2} O(l)$

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Solution

A substance is said to be oxidised if it gains oxygen and it is said to be reduced if it loses oxygen. In the given reaction, copper oxide $(CuO)$ is reduced to copper $(Cu)$ while hydrogen $(H_{2})$ is oxidized to water $(H_{2} O)$ .

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