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Division of a Polynomial by a Polynomial

Question 5ivF...

Question

Question 5(iv)
Factorise the expressions and divide them as directed
$4 y z (z^{2} + 6 z - 16) \div 2 y (z + 8)$

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Solution

$4 y z (z^{2} + 6 z - 16) = 4 y z [z^{2} - 2 z + 8 z - 16] = 4 y z [z (z - 2) + 8 (z - 2)] = 4 y z (z - 2) (z + 8) 4 y z (z^{2} + 6 z - 16) \div 2 y (z + 8) = \frac{4 y z (z - 2) (z + 8)}{2 y (z + 8)} = 2 z (z - 2)$

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Similar questions

Q. Question 5(iv)
Factorise the expressions and divide them as directed

4 y z (z^{2} + 6 z - 16) \div 2 y (z + 8)

Q. Factorise the expressions and divide them as directed.

4 y z (z^{2} + 6 z - 16) \div 2 y (z + 8)

Divide:
4 $y z (z^{2} + 6 z - 16)$ $\div 2 y (z + 8)$

4 y z (z^{2} + 6 z - 16) \div 2 y (z + 8)

Factorise the expressions and divide them as directed.

(i) (y² + 7y + 10) ÷ (y + 5)

(ii) (m² − 14m − 32) ÷ (m + 2)

(iii) (5p² − 25p + 20) ÷ (p − 1)

(iv) 4yz(z² + 6z − 16) ÷ 2y(z + 8)

(v) 5pq(p² − q²) ÷ 2p(p + q)

(vi) 12xy(9x² − 16y²) ÷ 4xy(3x + 4y)

(vii) 39y³(50y²− 98) ÷ 26y²(5y+ 7)

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Division of a Polynomial by a Polynomial

Standard VIII Mathematics

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