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Question

Question 5
Prove that the circle drawn with any side of a rhombus as diameter passes through the point of intersection of its diagonals.

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Solution


Let ABCD be a rhombus in which diagonals are intersecting at point O and a circle is drawn while taking side CD as its diameter.
We know that a diameter subtends 90 on the arc
COD=90
Also, in rhombus, the diagonals intersect each other at 90.
AOB=BOC=COD=DOA=90

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