Question

Question 7

In the given question, out of four options, only one is correct. Write the correct answer.

Let abc be a three-digit number. Then, abc + bca + cab is not divisible by
(a) a + b + c
(b) 3
(c) 37
(d) 9

Answer 1

We know that, the sum of three-digit numbers taken in cyclic order can be written as 111(a + b + c)
i.e. abc + bca + cab = $3\times 37\times (a+b+c)$
Hence, the sum is divisible by 3, 37 and (a + b + c) but not divisible by 9.