Question 88 (i)

Factorise the following expression.

$6 a b + 12 b c$

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Solution

We have,
$6 a b + 12 b c = 6 a b + 6 \times 2 \times b c = 6 b (a + 2 c)$

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6 a b + 12 b c

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Question 92 (i)

Factorise the following using the identity $a^{2} - b^{2} = (a + b) (a - b) .$

$x^{2} - 9$

a^{2} - 2 a b + b^{2} = (a - b)^{2}

x^{2} - 8 x + 16

x^{2} + 15 x + 26

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