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Question

Question 95

Solve the following question:

Write the Pythagorean triplet whose one of the numbers is 4.


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Solution

We know that, for any natural number greater than 1, (2m,m21,m2+1) is a Pythagorean triplet.
So, one number is 2m, then other two numbers are m2+1 and m21
Hence, one number is 4, then pythagorean triplet,
2m=4m=2
m2+1=22+1=4+1=5
and m21=221=41=3
Now, 32+42=52
9+16=2525=25
So 3, 4 and 5 are pythagorean triplets.


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