Ram walks 10 metres and Shyam walks 12 metres in the same time. They start together, how far behind will be Ram when Shyam has walked 288 metres?

50 m

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48 m

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4800 cm

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45 m

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Solution

The correct options are
B
48 m

C
4800 cm

Let us assume that they walk 10 m and 12 m respectively in 1 second.
The distance covered by Shyam is 288 m.

We know that, Distance = Speed x Time

Time taken by Shyam to cover 288 m = $\frac{288}{12}$ = 24 seconds
Therefore, the distance walked by Ram in 24 seconds = 24 x 10 = 240 m.

Hence, Ram is 288 - 240 = 48 m behind Shyam.

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