Question

# Ramesh bought two boxes for Rs. 1300. He sold one box at a profit of 20% and the other box at a loss of 12%. If the selling price of both boxes is the same, find the cost price of each box.

Solution

## Let the cost price of the first box be Rs. x.Therefore, the cost of the second box will be  Rs. (1300−x)Case 1:Profit  on the first box  =20%SP of the first box =(100+20)%×C.P=(120)%×x=120x100=6x5So, SP of the first box =6x5 ---(1)Case 2:Loss on the second box =12%SP of the second box =(100−12)%×C.P=(88)%×(1300−x)=88(1300−x)100So, SP of the second box =88(1300−x)100 ---(2)It is given that, selling price of both boxes is the same.⇒88(1300−x)100=6x5⇒5(88(1300−x))=600x⇒440(1300−x)=600x⇒44(1300−x)=60x⇒57200−44x=60x⇒57200=60x+44x⇒57200=104x⇒57200104=x⇒550=x⇒x=550Therefore, the cost price of the first box be Rs. 550.⇒ the cost price of the first box be Rs. (1300−550)=Rs. 750.MathematicsRD Sharma (2019, 2020)All

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