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Question

Ramesh bought two boxes for Rs. 1300. He sold one box at a profit of 20% and the other box at a loss of 12%. If the selling price of both boxes is the same, find the cost price of each box.


Solution

Let the cost price of the first box be Rs. x.

Therefore, the cost of the second box will be  Rs. (1300x)

Case 1:

Profit  on the first box  =20%

SP of the first box =(100+20)%×C.P

=(120)%×x

=120x100

=6x5

So, SP of the first box =6x5 ---(1)

Case 2:

Loss on the second box =12%

SP of the second box =(10012)%×C.P

=(88)%×(1300x)

=88(1300x)100

So, SP of the second box =88(1300x)100 ---(2)

It is given that, selling price of both boxes is the same.

88(1300x)100=6x5

5(88(1300x))=600x

440(1300x)=600x

44(1300x)=60x

5720044x=60x

57200=60x+44x

57200=104x

57200104=x

550=x

x=550

Therefore, the cost price of the first box be Rs. 550.

the cost price of the first box be Rs. (1300550)=Rs. 750.


Mathematics
RD Sharma (2019, 2020)
All

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