  Question

Ramesh bought two boxes for Rs. 1300. He sold one box at a profit of 20% and the other box at a loss of 12%. If the selling price of both boxes is the same, find the cost price of each box.

Solution

Let the cost price of the first box be Rs. x.Therefore, the cost of the second box will be  Rs. (1300−x)Case 1:Profit  on the first box  =20%SP of the first box =(100+20)%×C.P=(120)%×x=120x100=6x5So, SP of the first box =6x5 ---(1)Case 2:Loss on the second box =12%SP of the second box =(100−12)%×C.P=(88)%×(1300−x)=88(1300−x)100So, SP of the second box =88(1300−x)100 ---(2)It is given that, selling price of both boxes is the same.⇒88(1300−x)100=6x5⇒5(88(1300−x))=600x⇒440(1300−x)=600x⇒44(1300−x)=60x⇒57200−44x=60x⇒57200=60x+44x⇒57200=104x⇒57200104=x⇒550=x⇒x=550Therefore, the cost price of the first box be Rs. 550.⇒ the cost price of the first box be Rs. (1300−550)=Rs. 750.MathematicsRD Sharma (2019, 2020)All

Suggest Corrections  0  Similar questions
View More  Same exercise questions
View More 