Question

Ramu has an element $X$ with an Atomic Number of 13, while Somu has an element $Y$ with an Atomic Number of 16. If Ramu and Somu mix those elements and heat it, a new compound of $Z$ is formed.
Keeping this mind and answer the following question.
i) Write the electronic configuration of $X$.
ii) Write the electronic configuration of $Y$.
iii) Which one is a metal and which is a non-metal?
iv) What is the valency of $X$?
v) What is the valency of $Y$?
vi) Write the formula of $Z$.

Answer 1

(i) $X\left(13\right):1s^{2}2s^{2}2p^{6}3s^{2}3p^1$

(ii) $Y\left(16\right):1s^{2}2s^{2}2p^{6}3s^{2}3p^4$

(iii) $X$ can lose electron to gain noble gas configuration, similarly $Y$ can accept $2$ electrons. Hence $X$ is electropositive and $Y$ is electronegative. Therefore $X$ is a metal and $Y$ is non-metal.

(iv) $X$ can loose $3$ electrons to gain noble gas configuration. Hence its valency is $+3$.

(v) $Y$ can accept $2$ electrons to gain noble gas configuration. Hence its valency is $-2$.

(vi) Combination of $X^{3+}$ and $Y^{2-}$ will be $Z$ which is $X_2{Y}_3$.