H(x)=(x 2)/(x+3) The inverse function of the given function h(x) =(3x+2)/(1 x) The range of h is the domain of hand is given by the interval ( ∞, 1)∪ (1, ∞) ...

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Range of $\frac{(x - 2)}{(x + 3)}$

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Solution

$h (x) = \frac{(x - 2)}{(x + 3)}$ The inverse function of the given function h(x)
$= \frac{(3 x + 2)}{(1 - x)}$ The range of h is the domain of hand is given by the interval $(- \infty, 1) \cup (1, \infty)$

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Range of (x−2)(x+3)

h(x)=(x−2)(x+3) The inverse function of the given function h(x) =(3x+2)(1−x) The range of h is the domain of hand is given by the interval (−∞,1)∪(1,∞)

Range of $\frac{(x - 2)}{(x + 3)}$

$h (x) = \frac{(x - 2)}{(x + 3)}$ The inverse function of the given function h(x)
$= \frac{(3 x + 2)}{(1 - x)}$ The range of h is the domain of hand is given by the interval $(- \infty, 1) \cup (1, \infty)$