Question

# Range of the function $$f(x)={x}^{2}+\dfrac {1}{{x}^{2}+1}$$, is

A
[1,)
B
[2,)
C
[3,)
D
[0,)

Solution

## The correct option is A $$\left[1 , \infty \right)$$for $$f(x)$$ to be existed $$x^2+1>0$$but always $$x^2>=0$$put $$x=0$$$$f(x)=1$$this is the minimum value of $$f(x)$$maximum value can be infinitebecause $$x^2>=0$$range is $$[1,+\infty)$$Mathematics

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