CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

Range of the function $$f(x)={x}^{2}+\dfrac {1}{{x}^{2}+1}$$, is


A
[1,)
loader
B
[2,)
loader
C
[3,)
loader
D
[0,)
loader

Solution

The correct option is A $$\left[1 , \infty \right)$$
for $$f(x)$$ to be existed $$x^2+1>0$$
but always $$x^2>=0$$
put $$x=0$$
$$f(x)=1$$
this is the minimum value of $$f(x)$$
maximum value can be infinite
because $$x^2>=0$$
range is $$[1,+\infty)$$

Mathematics

Suggest Corrections
thumbs-up
 
0


similar_icon
Similar questions
View More


similar_icon
People also searched for
View More



footer-image