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Question

Rank the following in decreasing order of basic strength:
(i) CH3CH2CC
(ii) CH3CH2S
(iii) CH3CH2CO2
(iv) CH3CH2O.

A
(iv)>(i)>(ii)>(iii)
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B
(i)>(iv)>(ii)>(iii)
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C
(i)>(iv)>(iii)>(ii)
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D
(ii)>(i)>(iv)>(iii)
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Solution

The correct option is B (i)>(iv)>(ii)>(iii)
The gradation of acidic strength of organic compounds:
Acid >SH(Thiol) >OH(alcohol) > Alkyne

Here OH has a smaller bond length than SH so it's a weaker acid.
In alkyne, C is less electronegative than O so less acidic.

Hence, by Bronsted theory, strong acids have weak conjugate bases.
So Basicity order is:
Alkyne > Alcohol > Thiol > Acid
(i) > (iv) > (ii) > (iii)
Option: B

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