Question

# Ratio of amplitude of two waves is 1:16. The ratio of maximum to minimum intensity when the waves interfere is289:2253:11:256289:25

Solution

## The correct option is A 289:225A1A2=116 Maximum intensityMinimum intensity=(A1+A2)2(A1−A2)2=(1+16)2(1−16)2 Dividing by A22 in the numerator and denominator AmaxAmin=(17)2(15)2=289225=289:225

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