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Question

Ratio of amplitude of two waves is 1:16. The ratio of maximum to minimum intensity when the waves interfere is
  1. 289:225
  2. 3:1
  3. 1:256
  4. 289:25


Solution

The correct option is A 289:225
A1A2=116
Maximum intensityMinimum intensity=(A1+A2)2(A1A2)2=(1+16)2(116)2
Dividing by A22 in the numerator and denominator
AmaxAmin=(17)2(15)2=289225=289:225

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