Question

Rationalise the denominator in $\frac{2}{\sqrt{3}}$ .

• A. $\frac{2\sqrt{5}}{3}$
• B. $\frac{2\sqrt{2}}{3}$
• C. $\frac{2\sqrt{7}}{3}$
• D. $\frac{2\sqrt{3}}{3}$

Answer 1

The correct option is D

$\frac{2\sqrt{3}}{3}$

The least rationalising factor of $\sqrt{3}$ is $\sqrt{3}$ .

So, we multiply the numerator and denominator with $\sqrt{3}$ which gives

$\frac{2\times \sqrt{3}}{\sqrt{3}\times \sqrt{3}}$

$=\frac{2\sqrt{3}}{3}$