Question

Ravish has three boxes whose total weight is $60\frac{1}{2}$ kg. Box B weighs $3\frac{1}{2}$ kg more than box A and box C weighs more $5\frac{1}{3}$ kg more than box B. Find the weight of A,B and C.

Answer 1

Let the weight of box A be $x$ kg.

$\therefore$ Weight of box $B=(x+3\frac{1}{2})kg=(x+\frac{7}{2})kg$

And, Weight of box $C=[(x+\frac{7}{2})+5\frac{1}{3}]kg$$=(x+\frac{7}{2}+\frac{16}{3})kg$

Total weight of three boxes $=60\frac{1}{2}kg$$=\frac{121}{2}kg$

$\therefore x+(x+\frac{7}{2})+(x+\frac{7}{2}+\frac{16}{3})=\frac{121}{2}$

$\Rightarrow 3x=\frac{121}{2}-\frac{7}{2}-\frac{7}{2}-\frac{16}{3}$

$\Rightarrow 3x=\frac{121-7-7}{2}-\frac{16}{3}$

$\Rightarrow 3x=\frac{107}{2}-\frac{16}{3}$

$\Rightarrow 3x=\frac{321-32}{6}$

$\Rightarrow 3x=\frac{289}{6}$

$\Rightarrow x=\frac{289}{6\times 3}=\frac{289}{18}=16\frac{1}{18}kg$

$\therefore$ Weight of box A is $16\frac{1}{18}kg$.