Reaction of Acetamide with bromine water and KOH gives

CH₃COOH

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CH₃CH₂NH₂

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CH₃COONH₄

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CH₃NH₂

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Solution

The correct option is D CH₃NH₂
Hoffmann’s Bromamide reaction:
$C H_{3} C O N H_{2} + B r_{2} + 4 K O H ⟶ C H_{3} N H_{2} + K_{2} C O_{3} + 2 K B r + 2 H_{2} O$

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