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Question

# Reactions involving gold have been of particular interest to alchemists. Consider the following reactions, Au(OH)3+4 HCl→HAuCl4+3 H2O, △H=−28 kcal Au(OH)3+4 HBr→HAuBr4+3 H2O, △H=−36.8 kcal In an experiment, there was an absorption of 0.44 kcal when one mole of HAuBr4 was mixed with 4 moles of HCl. Then, the fraction of HAuBr4 converted into HAuCl4 (percentage conversion)

A
5%
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B
10%
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C
15%
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D
8%
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Solution

## The correct option is A 5%Au(OH)3+4 HCl→HAuCl4+3 H2O, △H=−28 kcal HAu(Br)4+3 H2O→Au(OH)3+4 HBr, △H=+36.8 kcal ___________________________________________________ HAuBr4+4 HCl→HAuCl4+4 HBr, △H=+8.8kcal When 100% conversion occurs, heat absorbed = 8.8 kcal % conversion =0.448.8×100=5

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