CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Real numbers a and b satisfy the equations 3a=81b+2 and 125b=5a−3 The value of ab is

A
17
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
9
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
12
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
60
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 60
3a=81b+2
3a=(34)b+2
3a=34b+8
Base are same so
a=4b+8
a4b=8.............eq1
125b=5a3
(53)b=5a3
53b=5a3
base are same so
3b=a3
a3b=3..............eq2
subtract eq1 and eq2
b=5
Substitute x=-5 in eq1
a+4(5)=8
a+20=8
a=12
Hence ab=12×5=60

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Properties of GP
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon