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Question

Reduce the expression into lowest form: $$\dfrac{x(x+1)}{x-2}\times \dfrac{1}{\frac{x}{(x+1)(x-2)}}$$


A
(x1)2
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B
(x+1)2
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C
(x2)2
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D
(x+1)
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Solution

The correct option is B $$(x+1)^2$$
$$\dfrac{x(x+1)}{x-2}\times \dfrac{1}{\frac{x}{(x+1)(x-2)}}$$
$$=$$ $$\dfrac{x(x+1)}{x-2}\times \dfrac{(x+1)(x-2)}{x}$$
$$=$$ $$(x+1)^2$$

Mathematics

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