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Question

Reduce the following equations into intercept form and find their intercepts on the axis.

(i) 3x + 2y - 1 2 = 0,    (ii) 4x- 3y = 6,    (iii) 3y + 2 = 0


Solution

(i) Here 3x + 2y - 12 = 0

3x + 2y = 12

   3x12+2y12=1    x4+y6=1

which is required intercept form.

Comparing it with xa+yb=1, we have

a = 4 and b=6

(ii) Here 4x - 3y = 6

    4x63y6=12x3y2=1

     x32+y2=1

 which is required intercept form.

Comparing it with xa+yb=1, we have

a=32 and b =-2

(iii) Here 3y + 2 = 0

    3y=2   3y2=1

     0x2+3y2=10x2+y23=1

which is required intercept form.

Comparing it with xa+yb=1, we have

a = 0 and b=23.

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