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Question

Question 6
Refer to Q.5. Draw the less than type and more than type ogive for the data and use them to find the median weight.

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Solution

Here, we observe that, the weight of all 70 packets is more than or equal to 200. Since, 13 packets lie in the interval 200-201. So, the weight of 70-13=57 packets is more than or equal to 201. Continuing in this manner we will get remaining more than or equal to 202, 203,204,205 and 206.
Weight (in g)Number of packetsNumber of packetsNumber of studentsLess than 200 0More than or equal to 20070Less than 201 13More than or equal to 2017013=57Less than 202 40More than or equal to 2025727=30Less than 203 58More than or equal to 2033018=12Less than 204 68More than or equal to 2041210=2Less than 205 69More than or equal to 20521=1Less than 206 70More than or equal to 20611=0
To draw the less than type ogive, we plot the points (200,0),(201,13),(202,40),(203,58),(204,68),(205,69),(206,70) on the paper and join them by free hand.
To draw the more than type ogive plot the points (200,70),(201,57),(202,30),(203,12),(204,2),(205,1),(206,0) on the graph paper and join them by free hand.


The abscissa(x-coordinate) where the two graphs meet is median =201.8 g

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