Relation between linear and angular magnification is

M_{a n g u l a r} = \frac{1}{M_{l a t e r a l}}

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M_{a n g u l a r} = M_{l a t e r a l}

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M_{a n g u l a r} - M_{l a t e r a l} = 1

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M_{a n g u l a r} + M_{l a t e r a l} = 1

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Solution

The correct option is A $M_{a n g u l a r} = \frac{1}{M_{l a t e r a l}}$
Relation between linear and angular magnification is
$M_{a n g u l a r} \times M_{l a t e r a l} = 1$ .

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