Represent the given statement in the form of inequation nbsp- Twice the length of a rectangle is less than area of the rectangle - nbsp-if length is represented using l nbsp-and area is represented using A-2l nbsp- gt- A2l nbsp- lt- Al nbsp- lt- 2Al nbsp- A

The correct option is B 2l nbsp; lt; AIf l nbsp; nbsp;= Length and A = nbsp; nbsp;area Twice the length nbsp; = 2 l ; Area = A nbsp; Hence 2l ...

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Standard VII

Mathematics

Inequations

Represent the...

Question

Represent the given statement in the form of inequation

Twice the length of a rectangle is less than area of the rectangle ; if length is represented using $l$ and area is represented using A.

2 l > A

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2 l < A

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l < 2 A

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l \leq A

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Solution

The correct option is B $2 l < A$
If $l$ = Length and A = area
Twice the length = 2 $l$ ;

Area = A
Hence 2 $l$ < A

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Represent the given statement in the form of inequation Twice the length of a rectangle is less than area of the rectangle ; if length is represented using l and area is represented using A.

The correct option is B 2l<AIf l = Length and A = area Twice the length = 2 l ; Area = A Hence 2l < A

Represent the given statement in the form of inequation

Twice the length of a rectangle is less than area of the rectangle ; if length is represented using $l$ and area is represented using A.

The correct option is B $2 l < A$
If $l$ = Length and A = area
Twice the length = 2 $l$ ;

Area = A
Hence 2 $l$ < A