State true or false- tan 1-tan 89-tan 2-tan 88-

The correct option is A Truetan1^∘.tan89^∘ = tan1^∘.cot(90^∘ 89^∘) = tan1^∘. cot1^∘ since, tanθ.cotθ = 1 = 1 similarly, tan2^∘.tan88^∘ = tan2^∘.cot(90^∘ 88 ...

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Byju's Answer

Standard X

Mathematics

Complementary Trigonometric Ratios

State true or...

Question

$S t a t e t r u e o r f a l s e .$
$t a n 1^{\circ} . t a n 89^{\circ} = t a n 2^{\circ} . t a n 88^{\circ}$

True

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False

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Solution

The correct option is A True
$t a n 1^{\circ} . t a n 89^{\circ} = t a n 1^{\circ} . c o t (90^{\circ} - 89^{\circ})$
$= t a n 1^{\circ} . c o t 1^{\circ}$
$s i n c e, t a n θ . c o t θ = 1$
$= 1$
$s i m i l a r l y, t a n 2^{\circ} . t a n 88^{\circ} = t a n 2^{\circ} . c o t (90^{\circ} - 88^{\circ})$
$t a n 2^{\circ} . c o t 2^{\circ} = 1$
$\Rightarrow t a n 1^{\circ} . t a n 89^{\circ} = t a n 2^{\circ} . t a n 88^{\circ}$

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Similar questions

$t a n 1^{\circ} . t a n 89^{\circ} = t a n 2^{\circ} . t a n 88^{\circ}$

P-1:-tan1.tan2.tan3......tan87.tan88.tan89=1

t a n 1^{\circ} . t a n 2^{\circ} . t a n 3^{\circ} . . . t a n 89^{\circ}

=_________.

tan 1^{\circ} tan 2^{\circ} tan 3^{\circ} . . . . . . . . . . . tan 89^{\circ} =

tan 1^{\circ} tan 2^{\circ} tan 3^{\circ} . . . tan 89^{\circ} =

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State true or false. tan1∘.tan89∘=tan2∘.tan88∘

The correct option is A Truetan1∘.tan89∘=tan1∘.cot(90∘−89∘) =tan1∘. cot1∘ since, tanθ.cotθ=1 =1 similarly,tan2∘.tan88∘=tan2∘.cot(90∘−88∘) tan2∘.cot2∘=1 ⇒tan1∘.tan89∘=tan2∘.tan88∘

$S t a t e t r u e o r f a l s e .$
$t a n 1^{\circ} . t a n 89^{\circ} = t a n 2^{\circ} . t a n 88^{\circ}$