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B
2,−32
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C
−2,−32
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D
2,32
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Solution
The correct option is A2,−32 Given quadratic equation is: 2x2−x−6=0 ⇒2x2−(4−3)x−6=0 ⇒2x2−4x+3x−6=0 ⇒(2x2−4x)+(3x−6)=0 ⇒2x(x−2)+3(x−2)=0 ⇒(x−2)(2x+3)=0 ⇒x−2=0 or 2x+3=0 ⇒x=2 or x=−32