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Question

Roots of quadratic equation $$2x^2 -x-6=0$$ are


A
2,32
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B
2,32
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C
2,32
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D
2,32
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Solution

The correct option is A $$2, \dfrac {-3}{2}$$
Given quadratic equation is:
$$2x^2-x-6=0$$
$$\Rightarrow 2x^2-(4-3)x-6=0$$
$$\Rightarrow 2x^2-4x+3x-6=0$$
$$\Rightarrow (2x^2-4x)+(3x-6)=0$$
$$\Rightarrow 2x(x-2)+3(x-2)=0$$
$$\Rightarrow (x-2)(2x+3)=0$$
$$\Rightarrow x-2=0$$ or $$2x+3=0$$
$$\Rightarrow x=2$$ or $$x=\dfrac {-3}{2}$$

Mathematics

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