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Question

Roots of quadratic equation $$3x^2\,+\,34x\,+\,11\,=\,0$$ are


A
11,13
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B
11,13
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C
11,13
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D
11,13
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Solution

The correct option is A $$\displaystyle\,-11,\,\frac{-1}{3}$$
Given equation is

$$3x^2 + 34x + 11 = 0 $$
$$3x^2 + 33x + x + 11 = 0 $$
$$(3x + 1) ( x + 11) = 0 $$
$$\therefore x = -11, \displaystyle \frac{-1}{3}$$
$$\therefore$$ roots of the given equation are $$-11, \displaystyle \frac {-1}{3}$$

Mathematics

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