Roots of quadratic equation $6 x^{2} - 7 x - 13 = 0$ are

- 1, \frac{13}{6}

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1, \frac{- 13}{6}

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- 1, \frac{- 13}{6}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1, \frac{13}{6}

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Solution

The correct option is D $- 1, \frac{13}{6}$
Given equation is:
$6 x^{2} - 7 x - 13 = 0$
$6 x^{2} - 13 x + 6 x - 13 = 0$
$6 x (x + 1) - 13 (x + 1) = 0$
$(6 x - 13) (x + 1) = 0$
$∴ x = \frac{13}{6}, - 1$
$∴$ roots of the given equation are $- 1, \frac{13}{6}$

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Find the roots of the quadratic equation $6 x^{2} - 13 x + 6 = 0$ by using the quadratic formula.

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