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Question

Rs 2250 is divided among three friends Amar, Bijoy and Chandra in such a way that 16 th of Amar's share, 14 th of Bijoy's share and 25 th of Chandra's share are equal. Find Amar's share.
  1. Rs 720
  2. Rs 1080
  3. Rs 450
  4. Rs 1240


Solution

The correct option is B Rs 1080
According to question,
A6=B4=2C5
Multiplying all three fractions by LCM(6, 4, 5), we get
10A = 15B = 24C
Hence, A+2A3+5A12=2250
On solving, Amar's share = Rs.1080

Alternative Approach:
Amar's share should be divisible by 6. Option d gets rejected by this logic.
Further: A + B + C = 2250. If Amar's share is 720 (acc. To option a) Bijoy's share should be 480 & Chandra's share should be 300. (Gives us a total of 720 + 480 + 300 = 1500).
But the required total is 2250 (50% more than 1500). Since all relationships are linear, 1500 will increase to 2250 if we increase all values by 50%. Hence, Amar's share should be 1080.

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