Rukshar painted the outside of the cabinet to measure 1 m - 2 m - 1-5 m - How much surface area did she cover if she painted all except the bottom of the cabinet-

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Standard IX

Mathematics

Lateral surface Area of cuboid

Rukshar paint...

Question

Rukshar painted the outside of the cabinet to measure $1 m$ $\times 2 m$ $\times 1.5 m$ . How much surface area did she cover if she painted all except the bottom of the cabinet?

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Solution

Surface area of cabinet:
Length of the cabinet, $l = 2 m$
The breadth of the cabinet, $b = 1 m$
Height of cabinet, $h = 1.5 m$
The surface area of the cabinet $= l b + 2 (b h + h l)$
$= 2 \times 1 + 2 (1 \times 1.5 + 1.5 \times 2) = 2 + 2 (1.5 + 3.0) = 2 + 9.0 = 11$
Thus,the required surface area of the cabinet is $11 m^{2}$ .

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Rukshar painted the outside of the cabinet to measure 1m ×2m ×1.5m . How much surface area did she cover if she painted all except the bottom of the cabinet?

Surface area of cabinet:Length of the cabinet, l=2m The breadth of the cabinet, b=1mHeight of cabinet, h=1.5mThe surface area of the cabinet =lb+2(bh+hl) =2×1+2(1×1.5+1.5×2)=2+2(1.5+3.0)=2+9.0=11 Thus,the required surface area of the cabinet is 11m2.

Rukshar painted the outside of the cabinet to measure $1 m$ $\times 2 m$ $\times 1.5 m$ . How much surface area did she cover if she painted all except the bottom of the cabinet?