Byju's Answer

Standard VIII

Mathematics

Word Problems in Addition and Subtraction

Santosh has x...

Question

Santosh has x pens, and y pencils . Anjan has 3 pens less than Santosh, but thrice as many pencils. The expression for the total number of pencils and pens with Anjan is:

6x + 3y - 3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x + 4y - 3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x + 3y - 2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x + 3y - 3

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D
x + 3y - 3

Anjan has 3 pens less than Santosh => x- 3

Thrice as many pencils => 3y

Total number of pencils and pens with Anjan = x + 3y - 3

Suggest Corrections

Similar questions

Santosh has $x$ pens, and $y$ pencils. Anjan has 3 pens less than Santosh and thrice the number of pencils. The expression for the total number of pens and pencils with Anjan is:

Q. Reena has pens and pencils which together are

40

in number. If she has

5

more pencils and

5

less pens, the number of pencils would become

4

times the number of pens. Find the original number of pens and pencils.

Reena has. Pens and pencils which together are 40 in number. If she has 5 more pencils and 5 less pens,then number of pencils would become 4 times the number of pens . Find original number of pens and pencils.

Q. There are 5 pencils and 3 times as many pens. What is the total number of pens and pencils?

X

has pens and pencils which together are

40

in number. If he had

5

more pencils and

5

less pens, the number of pencils would have become

4

times the number of pens. Find the original number of pens.

Santosh has x pens, and y pencils . Anjan has 3 pens less than Santosh, but thrice as many pencils. The expression for the total number of pencils and pens with Anjan is:

The correct option is D x + 3y - 3 Anjan has 3 pens less than Santosh => x- 3 Thrice as many pencils => 3y Total number of pencils and pens with Anjan = x + 3y - 3

The correct option is D
x + 3y - 3

Anjan has 3 pens less than Santosh => x- 3

Thrice as many pencils => 3y

Total number of pencils and pens with Anjan = x + 3y - 3