Question

Sanya, Aarushi, Manav and Kabir made greeting cards. Complete the table for their cards:

Whose card	Length	Width	Perimeter	Area
Sanya	10 cm	8 cm
Manav	11 cm		44 cm
Aarushi		8 cm		80 square cm
Kabir			40 cm	100 square cm

Answer 1

Perimeter of Sanya's card = Sum of all its sides = 10 + 8 + 10 + 8 = 36 cm

Length of Manav's card = 11 cm
Perimeter of his card = 44 cm

We have to find the width of Manav's card.

Perimeter of card = Sum of all its sides
= 11 + 11 + sum of 2 other sides
= 22 + sum of 2 other sides

Now, sum of two other sides = 44 − 22
= 22 cm
The two other sides of the greeting cards are width.
So, width of Manav's card = 22 $÷$ 2
= 11 cm

Width of Aarushi's card = 8 cm
Area of the card = 80 square cm

Now, we have to find length of the card.

Area of card = Length of card $\times$ 8 cm = 80 square cm
So, on dividing the area of card by its width, we can get its length.
Therefore, length of Aarushi's card = 80 $÷$ 8
= 10 cm

Whose card	Length	Width	Perimeter	Area
Sanya	10 cm	8 cm	36 cm	80 square cm
Manav	11 cm	11 cm	44 cm	121 square cm
Aarushi	10 cm	8 cm	36 cm	80 square cm
Kabir	10 cm	10 cm	40 cm	100 square cm